写出程序计算所有 (n+1)(m+1)(n + 1)(m + 1) 种状态是必胜态还是必败态。列出表格,观察图形性质,可得:

nmod3=n \bmod 3 = mmod6=m \bmod 6 = 答案
00 00 Sleeping Alligator
11 Sleeping Iguana
22
33 Sleeping Alligator
44
55
11 00 Sleeping Iguana
11 Sleeping Alligator
22 Sleeping Iguana
33 Sleeping Alligator
44 Sleeping Iguana
55
22 00 Sleeping Alligator
11 Sleeping Iguana
22 Sleeping Alligator
33 Sleeping Iguana
44
55
#include <bits/stdc++.h>
using namespace std;
const string names[2] =
{
	"Sleeping Iguana",
	"Sleeping Alligator"
};
const int results[3][6] =
{
	{1, 0, 0, 1, 1, 1},
	{0, 1, 0, 1, 0, 0},
	{1, 0, 1, 0, 0, 0}
};
int main()
{
	freopen("savings.in", "r", stdin);
	freopen("savings.out", "w", stdout);
	int T, n, m;
	cin >> T;
	while (cin >> n >> m) cout << names[results[n % 3][m % 6]] << endl;
	return 0;
}